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CUET PG MCA Ratio Proportion And Variation PYQ


CUET PG MCA PYQ
In a class, 4/5 of the students are boys and rest are girls. If 2/5 of the boys and 1/4 of girls are absent, what part of the total number of students is present?





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CUET PG MCA Previous Year PYQCUET PG MCA CUET 2024 PYQ

Solution

Solution

Given: 4/5 of the students are boys, and the rest are girls. 2/5 of boys and 1/4 of girls are absent.

Step-by-Step Solution

  • Total students = N
  • Boys: (4/5) × N = 4N/5
  • Girls: (1/5) × N = N/5
  • Boys absent: (2/5) × (4N/5) = 8N/25
  • Girls absent: (1/4) × (N/5) = N/20
  • Boys present: (4N/5 - 8N/25 = 12N/25)
  • Girls present: (N/5 - N/20 = 3N/20)
  • Total present = (12N/25 + 3N/20)

Final Calculation

LCM of 25 and 20 is 100:
(12N/25 = 48N/100), (3N/20 = 15N/100)
Total present = (48N/100 + 15N/100 = 63N/100)

Answer: 63/100



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